给你一个日期，请你设计一个算法来判断它是对应一周中的哪一天。
输入为三个整数：day、month 和 year，分别表示日、月、年。
您返回的结果必须是这几个值中的一个 {“Sunday”, “Monday”, “Tuesday”, “Wednesday”, “Thursday”, “Friday”, “Saturday”}。
来源：力扣（LeetCode）
链接：https://leetcode.cn/problems/day-of-the-week
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思路：python都写好了，我直接拿来用
python3实现：
class Solution:
def dayOfTheWeek(self, day: int, month: int, year: int) -> str:
# 直接调用datetime函数
# 用给的day，month，year构造日期
if len(str(day)) == 1:
day = "0" + str(day)
else:
day = str(day)
if len(str(month)) == 1:
month = "0" + str(month)
else:
month = str(month)
year = str(year)
str_date = year + month + day
list_week = ["Monday", "Tuesday", "Wednesday", "Thursday", "Friday", "Saturday","Sunday"]
result = datetime.datetime.strptime(str_date, "%Y%m%d").weekday() + 1
return list_week[result-1]
